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Hitunglah jumlah Network dan Host yang akan terbentuk dari alamat IP Address dibawah ini: 1.    192.168.10.1/30 2.    172.168.10.1/16 3.    172.168.10./22 4.    10.168.5.1/8 5.    10.168.5.1/17 Jawaban: Nomer 1:  192.168.10.1/30 Netmask = 255.255.255.252 In binary = 11111111. 11111111. 11111111. 11111100 Used to calculate = 11111100 Network = 2^n  = 2^6  = 64 Network Host = 2^h-2      = 2^2-2      = 2 Host Nomer 2:  172.168.10.1/16 Netmask = 255.255.0.0 In Binary = 11111111.11111111. 00000000 . 00000000 Used to calculate = 00000000 . 00000000 Network = 2^n         = 2^0         = 1 Network Host    = 2^h-2  = 2^16-2  = 65534 Host Nomer 3:  172.168.10./22 Netmask : 255.255.252.0 In Binary : 11111111.11111111. 11111100 . 00000000 Used to calculate = 11111100 . 00000000 Network = 2...